Solve 2r^2-3p-7=0

$$2 r ^ { 2 } - 3 p - 7 = 0$$

Solve for p

$$p=\frac{2r^{2}-7}{3}$$

Steps for Solving Linear Equation

Subtract 2r^{2} from both sides. Anything subtracted from zero gives its negation.

$$-3p-7=-2r^{2}$$

Add 7 to both sides.

$$-3p=-2r^{2}+7$$

The equation is in standard form.

$$-3p=7-2r^{2}$$

Divide both sides by -3.

$$\frac{-3p}{-3}=\frac{7-2r^{2}}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$p=\frac{7-2r^{2}}{-3}$$

Divide -2r^{2}+7 by -3.

$$p=\frac{2r^{2}-7}{3}$$

Solve for r

$$r=\frac{\sqrt{6p+14}}{2}$$

$$r=-\frac{\sqrt{6p+14}}{2}\text{, }p\geq -\frac{7}{3}$$