Solve 2p+(3q+2)=(2p+3q)+2

$$2 p + ( 3 q + 2 ) = ( 2 p + 3 q ) + 2$$

Solve for p (complex solution)

$$p\in \mathrm{C}$$

Solution Steps

Subtract 2p from both sides.

$$2p+3q+2-2p=3q+2$$

Combine 2p and -2p to get 0.

$$3q+2=3q+2$$

Reorder the terms.

$$\text{true}$$

This is true for any p.

$$p\in \mathrm{C}$$

Solve for q (complex solution)

$$q\in \mathrm{C}$$

Solution Steps

Subtract 3q from both sides.

$$2p+3q+2-3q=2p+2$$

Combine 3q and -3q to get 0.

$$2p+2=2p+2$$

Reorder the terms.

$$\text{true}$$

This is true for any q.

$$q\in \mathrm{C}$$

Solve for p

$$p\in \mathrm{R}$$

Solution Steps

Subtract 2p from both sides.

$$2p+3q+2-2p=3q+2$$

Combine 2p and -2p to get 0.

$$3q+2=3q+2$$

Reorder the terms.

$$\text{true}$$

This is true for any p.

$$p\in \mathrm{R}$$

Solve for q

$$q\in \mathrm{R}$$

Solution Steps

Subtract 3q from both sides.

$$2p+3q+2-3q=2p+2$$

Combine 3q and -3q to get 0.

$$2p+2=2p+2$$

Reorder the terms.

$$\text{true}$$

This is true for any q.

$$q\in \mathrm{R}$$