Solve 2n12x+2(n+n)=36

$$2 n 12 x + 2 ( n + n ) = 36$$

Solve for n_12 (complex solution)

$$\left\{\begin{matrix}n_{12}=-\frac{2\left(n-9\right)}{x}\text{, }&x\neq 0\\n_{12}\in \mathrm{C}\text{, }&n=9\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Combine n and n to get 2n.

$$2n_{12}x+2\times 2n=36$$

Multiply 2 and 2 to get 4.

$$2n_{12}x+4n=36$$

Subtract 4n from both sides.

$$2n_{12}x=36-4n$$

The equation is in standard form.

$$2xn_{12}=36-4n$$

Divide both sides by 2x.

$$\frac{2xn_{12}}{2x}=\frac{36-4n}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$n_{12}=\frac{36-4n}{2x}$$

Divide 36-4n by 2x.

$$n_{12}=\frac{2\left(9-n\right)}{x}$$

Solve for n

$$n=-\frac{n_{12}x}{2}+9$$

Steps for Solving Linear Equation

Combine n and n to get 2n.

$$2n_{12}x+2\times 2n=36$$

Multiply 2 and 2 to get 4.

$$2n_{12}x+4n=36$$

Subtract 2n_{12}x from both sides.

$$4n=36-2n_{12}x$$

Divide both sides by 4.

$$\frac{4n}{4}=\frac{36-2n_{12}x}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$n=\frac{36-2n_{12}x}{4}$$

Divide 36-2n_{12}x by 4.

$$n=-\frac{n_{12}x}{2}+9$$

Solve for n_12

$$\left\{\begin{matrix}n_{12}=-\frac{2\left(n-9\right)}{x}\text{, }&x\neq 0\\n_{12}\in \mathrm{R}\text{, }&n=9\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Combine n and n to get 2n.

$$2n_{12}x+2\times 2n=36$$

Multiply 2 and 2 to get 4.

$$2n_{12}x+4n=36$$

Subtract 4n from both sides.

$$2n_{12}x=36-4n$$

The equation is in standard form.

$$2xn_{12}=36-4n$$

Divide both sides by 2x.

$$\frac{2xn_{12}}{2x}=\frac{36-4n}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$n_{12}=\frac{36-4n}{2x}$$

Divide 36-4n by 2x.

$$n_{12}=\frac{2\left(9-n\right)}{x}$$