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2n-\frac{3}{4}+\frac{8}{4}-5\sqrt{3}=\frac{1}{2}\pi
Convert 2 to fraction \frac{8}{4}.
2n+\frac{-3+8}{4}-5\sqrt{3}=\frac{1}{2}\pi
Since -\frac{3}{4} and \frac{8}{4} have the same denominator, add them by adding their numerators.
2n+\frac{5}{4}-5\sqrt{3}=\frac{1}{2}\pi
Add -3 and 8 to get 5.
2n-5\sqrt{3}=\frac{1}{2}\pi -\frac{5}{4}
Subtract \frac{5}{4} from both sides.
2n=\frac{1}{2}\pi -\frac{5}{4}+5\sqrt{3}
Add 5\sqrt{3} to both sides.
2n=\frac{\pi }{2}+5\sqrt{3}-\frac{5}{4}
The equation is in standard form.
\frac{2n}{2}=\frac{\frac{\pi }{2}+5\sqrt{3}-\frac{5}{4}}{2}
Divide both sides by 2.
n=\frac{\frac{\pi }{2}+5\sqrt{3}-\frac{5}{4}}{2}
Dividing by 2 undoes the multiplication by 2.
n=\frac{\pi }{4}+\frac{5\sqrt{3}}{2}-\frac{5}{8}
Divide \frac{\pi }{2}-\frac{5}{4}+5\sqrt{3} by 2.