Solve 2n*n

$$2 n \times n$$

Differentiate w.r.t. n

$$4n$$

Steps Using Definition of a Derivative

Multiply n and n to get n^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}n}(2n^{2})$$

The derivative of ax^{n} is nax^{n-1}.

$$2\times 2n^{2-1}$$

Multiply 2 times 2.

$$4n^{2-1}$$

Subtract 1 from 2.

$$4n^{1}$$

For any term t, t^{1}=t.

$$4n$$

Evaluate

$$2n^{2}$$

Solution Steps

Multiply n and n to get n^{2}.

$$2n^{2}$$