Solve 2mn*6m*7mn*2i=

$$2 m n \cdot 6 m \cdot 7 m n \cdot 2 i =$$

Evaluate

$$168in^{2}m^{3}$$

Solution Steps

Multiply m and m to get m^{2}.

$$2m^{2}n\times 6\times 7mn\times \left(2i\right)$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$2m^{3}n\times 6\times 7n\times \left(2i\right)$$

Multiply n and n to get n^{2}.

$$2m^{3}n^{2}\times 6\times 7\times \left(2i\right)$$

Multiply 2 and 6 to get 12.

$$12m^{3}n^{2}\times 7\times \left(2i\right)$$

Multiply 12 and 7 to get 84.

$$84m^{3}n^{2}\times \left(2i\right)$$

Multiply 84 and 2i to get 168i.

$$168im^{3}n^{2}$$