Solve 2m^3-8m=

$$2 m ^ { 3 } - 8 m =$$

Factor

$$2m\left(m-2\right)\left(m+2\right)$$

Solution Steps

Factor out 2.

$$2\left(m^{3}-4m\right)$$

Consider m^{3}-4m. Factor out m.

$$m\left(m^{2}-4\right)$$

Consider m^{2}-4. Rewrite m^{2}-4 as m^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(m-2\right)\left(m+2\right)$$

Rewrite the complete factored expression.

$$2m\left(m-2\right)\left(m+2\right)$$

Evaluate

$$2m\left(m^{2}-4\right)$$