Evaluate
10+6i
Real Part
10
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2i\times 3+2\left(-5\right)i^{2}
Multiply 2i times 3-5i.
2i\times 3+2\left(-5\right)\left(-1\right)
By definition, i^{2} is -1.
10+6i
Do the multiplications. Reorder the terms.
Re(2i\times 3+2\left(-5\right)i^{2})
Multiply 2i times 3-5i.
Re(2i\times 3+2\left(-5\right)\left(-1\right))
By definition, i^{2} is -1.
Re(10+6i)
Do the multiplications in 2i\times 3+2\left(-5\right)\left(-1\right). Reorder the terms.
10
The real part of 10+6i is 10.
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