Solve 2hj^{1-2}k^-2*h^4j^-1k^4

$$2 h j ^ { 1 - 2 } k ^ { - 2 } \cdot h ^ { 4 } j ^ { - 1 } k ^ { 4 }$$

Evaluate

$$2\times \left(\frac{k}{j}\right)^{2}h^{5}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 4 to get 5.

$$2h^{5}j^{1-2}k^{-2}j^{-1}k^{4}$$

To multiply powers of the same base, add their exponents. Add -2 and 4 to get 2.

$$2h^{5}j^{1-2}k^{2}j^{-1}$$

Subtract 2 from 1 to get -1.

$$2h^{5}j^{-1}k^{2}j^{-1}$$

To multiply powers of the same base, add their exponents. Add -1 and -1 to get -2.

$$2h^{5}j^{-2}k^{2}$$

Differentiate w.r.t. k

$$\frac{4kh^{5}}{j^{2}}$$