Factor
2\left(h-2\right)\left(h^{2}+2h+4\right)
Evaluate
2\left(h^{3}-8\right)
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2\left(h^{3}-8\right)
Factor out 2.
\left(h-2\right)\left(h^{2}+2h+4\right)
Consider h^{3}-8. Rewrite h^{3}-8 as h^{3}-2^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
2\left(h-2\right)\left(h^{2}+2h+4\right)
Rewrite the complete factored expression. Polynomial h^{2}+2h+4 is not factored since it does not have any rational roots.
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