Solve 2h^2+3k-1=0

$$2 h ^ { 2 } + 3 k - 1 = 0$$

Solve for k

$$k=\frac{1-2h^{2}}{3}$$

Steps for Solving Linear Equation

Subtract 2h^{2} from both sides. Anything subtracted from zero gives its negation.

$$3k-1=-2h^{2}$$

Add 1 to both sides.

$$3k=-2h^{2}+1$$

The equation is in standard form.

$$3k=1-2h^{2}$$

Divide both sides by 3.

$$\frac{3k}{3}=\frac{1-2h^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$k=\frac{1-2h^{2}}{3}$$

Solve for h

$$h=\frac{\sqrt{2-6k}}{2}$$

$$h=-\frac{\sqrt{2-6k}}{2}\text{, }k\leq \frac{1}{3}$$