Solve 2f(-4)+5f(0)+2f(-2)-f(4)quadTheta

$$2 f ( - 4 ) + 5 f ( 0 ) + 2 f ( - 2 ) - f ( 4 ) \quad \Theta$$

Evaluate

$$-4f\Theta -12f$$

Solution Steps

Multiply 2 and -4 to get -8.

$$-8f+5f\times 0+2f\left(-2\right)-f\times 4\Theta$$

Multiply 5 and 0 to get 0.

$$-8f+0f+2f\left(-2\right)-f\times 4\Theta$$

Anything times zero gives zero.

$$-8f+0+2f\left(-2\right)-f\times 4\Theta$$

Multiply 2 and -2 to get -4.

$$-8f+0-4f-f\times 4\Theta$$

Combine -8f and -4f to get -12f.

$$-12f+0-f\times 4\Theta$$

Anything plus zero gives itself.

$$-12f-f\times 4\Theta$$

Multiply -1 and 4 to get -4.

$$-12f-4f\Theta$$

Factor

$$4f\left(-\Theta -3\right)$$

Solution Steps

Factor out 4.

$$4\left(-2f+0-f-f\Theta \right)$$

Consider -2f-f-f\Theta . Factor out f.

$$f\left(-3-\Theta \right)$$

Consider -2-1-\Theta . Multiply and combine like terms.

$$-\Theta -3$$

Rewrite the complete factored expression.

$$4f\left(-\Theta -3\right)$$