Solve 2cq=cq+F/q

$$2 c q = c q + \frac { F } { q }$$

Solve for F

$$F=cq^{2}$$

$$q\neq 0$$

Solution Steps

Multiply both sides of the equation by q.

$$2cqq=cqq+F$$

Multiply q and q to get q^{2}.

$$2cq^{2}=cqq+F$$

Multiply q and q to get q^{2}.

$$2cq^{2}=cq^{2}+F$$

Swap sides so that all variable terms are on the left hand side.

$$cq^{2}+F=2cq^{2}$$

Subtract cq^{2} from both sides.

$$F=2cq^{2}-cq^{2}$$

Combine 2cq^{2} and -cq^{2} to get cq^{2}.

$$F=cq^{2}$$

Solve for c

$$c=\frac{F}{q^{2}}$$

$$q\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by q.

$$2cqq=cqq+F$$

Multiply q and q to get q^{2}.

$$2cq^{2}=cqq+F$$

Multiply q and q to get q^{2}.

$$2cq^{2}=cq^{2}+F$$

Subtract cq^{2} from both sides.

$$2cq^{2}-cq^{2}=F$$

Combine 2cq^{2} and -cq^{2} to get cq^{2}.

$$cq^{2}=F$$

The equation is in standard form.

$$q^{2}c=F$$

Divide both sides by q^{2}.

$$\frac{q^{2}c}{q^{2}}=\frac{F}{q^{2}}$$

Dividing by q^{2} undoes the multiplication by q^{2}.

$$c=\frac{F}{q^{2}}$$