Solve 2b-x=3+2bx

$$2 b - x = 3 + 2 b x$$

Solve for b

$$b=\frac{x+3}{2\left(1-x\right)}$$

$$x\neq 1$$

Steps for Solving Linear Equation

Subtract 2bx from both sides.

$$2b-x-2bx=3$$

Add x to both sides.

$$2b-2bx=3+x$$

Combine all terms containing b.

$$\left(2-2x\right)b=3+x$$

The equation is in standard form.

$$\left(2-2x\right)b=x+3$$

Divide both sides by -2x+2.

$$\frac{\left(2-2x\right)b}{2-2x}=\frac{x+3}{2-2x}$$

Dividing by -2x+2 undoes the multiplication by -2x+2.

$$b=\frac{x+3}{2-2x}$$

Divide x+3 by -2x+2.

$$b=\frac{x+3}{2\left(1-x\right)}$$

Solve for x

$$x=\frac{2b-3}{2b+1}$$

$$b\neq -\frac{1}{2}$$

Steps for Solving Linear Equation

Subtract 2bx from both sides.

$$2b-x-2bx=3$$

Subtract 2b from both sides.

$$-x-2bx=3-2b$$

Combine all terms containing x.

$$\left(-1-2b\right)x=3-2b$$

The equation is in standard form.

$$\left(-2b-1\right)x=3-2b$$

Divide both sides by -1-2b.

$$\frac{\left(-2b-1\right)x}{-2b-1}=\frac{3-2b}{-2b-1}$$

Dividing by -1-2b undoes the multiplication by -1-2b.

$$x=\frac{3-2b}{-2b-1}$$

Divide 3-2b by -1-2b.

$$x=-\frac{3-2b}{2b+1}$$