Solve 2b^4-b^3-2b+1divb^3-1

$$2 b ^ { 4 } - b ^ { 3 } - 2 b + 1 \div b ^ { 3 } - 1$$

Evaluate

$$2b^{4}-b^{3}-2b-1+\frac{1}{b^{3}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2b^{4}-b^{3}-2b-1 times \frac{b^{3}}{b^{3}}.

$$\frac{\left(2b^{4}-b^{3}-2b-1\right)b^{3}}{b^{3}}+\frac{1}{b^{3}}$$

Since \frac{\left(2b^{4}-b^{3}-2b-1\right)b^{3}}{b^{3}} and \frac{1}{b^{3}} have the same denominator, add them by adding their numerators.

$$\frac{\left(2b^{4}-b^{3}-2b-1\right)b^{3}+1}{b^{3}}$$

Do the multiplications in \left(2b^{4}-b^{3}-2b-1\right)b^{3}+1.

$$\frac{2b^{7}-b^{6}-2b^{4}-b^{3}+1}{b^{3}}$$

Factor

$$\frac{2b^{7}-b^{6}-2b^{4}-b^{3}+1}{b^{3}}$$