Factor
2\left(b-5c\right)\left(b^{2}+5bc+25c^{2}\right)
Evaluate
2\left(b^{3}-125c^{3}\right)
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2\left(b^{3}-125c^{3}\right)
Factor out 2.
\left(b-5c\right)\left(b^{2}+5bc+25c^{2}\right)
Consider b^{3}-125c^{3}. Rewrite b^{3}-125c^{3} as b^{3}-\left(5c\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
2\left(b-5c\right)\left(b^{2}+5bc+25c^{2}\right)
Rewrite the complete factored expression.
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