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2\left(b^{3}-1\right)
Factor out 2.
\left(b-1\right)\left(b^{2}+b+1\right)
Consider b^{3}-1. Rewrite b^{3}-1 as b^{3}-1^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
2\left(b-1\right)\left(b^{2}+b+1\right)
Rewrite the complete factored expression. Polynomial b^{2}+b+1 is not factored since it does not have any rational roots.