Factor
\left(2x-1\right)\left(b^{2}-3a\right)
Evaluate
\left(2x-1\right)\left(b^{2}-3a\right)
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b^{2}\left(2x-1\right)-3a\left(2x-1\right)
Do the grouping 2b^{2}x-b^{2}-6ax+3a=\left(2b^{2}x-b^{2}\right)+\left(-6ax+3a\right), and factor out b^{2} in the first and -3a in the second group.
\left(2x-1\right)\left(b^{2}-3a\right)
Factor out common term 2x-1 by using distributive property.
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