Solve 2b^2+17b^2-21

$$2 b ^ { 2 } + 17 b ^ { 2 } - 21$$

Differentiate w.r.t. b

$$38b$$

Steps Using Derivative Rule for Sum

Combine 2b^{2} and 17b^{2} to get 19b^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}b}(19b^{2}-21)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\times 19b^{2-1}$$

Multiply 2 times 19.

$$38b^{2-1}$$

Subtract 1 from 2.

$$38b^{1}$$

For any term t, t^{1}=t.

$$38b$$

Evaluate

$$19b^{2}-21$$

Solution Steps

Combine 2b^{2} and 17b^{2} to get 19b^{2}.

$$19b^{2}-21$$