Solve 2ax-b=c

$$2 a x - b = c$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{b+c}{2x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=-c\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add b to both sides.

$$2ax=c+b$$

The equation is in standard form.

$$2xa=b+c$$

Divide both sides by 2x.

$$\frac{2xa}{2x}=\frac{b+c}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$a=\frac{b+c}{2x}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{b+c}{2x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=-c\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add b to both sides.

$$2ax=c+b$$

The equation is in standard form.

$$2xa=b+c$$

Divide both sides by 2x.

$$\frac{2xa}{2x}=\frac{b+c}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$a=\frac{b+c}{2x}$$

Solve for b

$$b=2ax-c$$

Steps for Solving Linear Equation

Subtract 2ax from both sides.

$$-b=c-2ax$$

Divide both sides by -1.

$$\frac{-b}{-1}=\frac{c-2ax}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$b=\frac{c-2ax}{-1}$$

Divide c-2ax by -1.

$$b=-\left(c-2ax\right)$$