Solve 2ac=6+c^2

$$2 a c = 6 + c ^ { 2 }$$

Solve for a

$$a=\frac{c}{2}+\frac{3}{c}$$

$$c\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$2ca=c^{2}+6$$

Divide both sides by 2c.

$$\frac{2ca}{2c}=\frac{c^{2}+6}{2c}$$

Dividing by 2c undoes the multiplication by 2c.

$$a=\frac{c^{2}+6}{2c}$$

Divide 6+c^{2} by 2c.

$$a=\frac{c}{2}+\frac{3}{c}$$

Solve for c

$$c=-\sqrt{a^{2}-6}+a$$

$$c=\sqrt{a^{2}-6}+a\text{, }|a|\geq \sqrt{6}$$