Solve 2a-8(4/3-2a/3)=

$$2 a - 8 ( \frac { 4 } { 3 } - \frac { 2 a } { 3 } ) =$$

Evaluate

$$\frac{22a-32}{3}$$

Short Solution Steps

Since \frac{4}{3} and \frac{2a}{3} have the same denominator, add them by adding their numerators.

$$2a-8\times \frac{4+2a}{3}$$

Express 8\times \frac{4+2a}{3} as a single fraction.

$$2a-\frac{8\left(4+2a\right)}{3}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2a times \frac{3}{3}.

$$\frac{3\times 2a}{3}-\frac{8\left(4+2a\right)}{3}$$

Since \frac{3\times 2a}{3} and \frac{8\left(4+2a\right)}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\times 2a-8\left(4+2a\right)}{3}$$

Do the multiplications in 3\times 2a-8\left(4+2a\right).

$$\frac{6a-32-16a}{3}$$

Combine like terms in 6a-32-16a.

$$\frac{-10a-32}{3}$$

Expand

$$\frac{22a-32}{3}$$

Short Solution Steps

Since \frac{4}{3} and \frac{2a}{3} have the same denominator, add them by adding their numerators.

$$2a-8\times \frac{4+2a}{3}$$

Express 8\times \frac{4+2a}{3} as a single fraction.

$$2a-\frac{8\left(4+2a\right)}{3}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2a times \frac{3}{3}.

$$\frac{3\times 2a}{3}-\frac{8\left(4+2a\right)}{3}$$

Since \frac{3\times 2a}{3} and \frac{8\left(4+2a\right)}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\times 2a-8\left(4+2a\right)}{3}$$

Do the multiplications in 3\times 2a-8\left(4+2a\right).

$$\frac{6a-32-16a}{3}$$

Combine like terms in 6a-32-16a.

$$\frac{-10a-32}{3}$$