Solve for a
a=\frac{5b+3}{2}
Solve for b
b=\frac{2a-3}{5}
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2a=3+5b
Add 5b to both sides.
2a=5b+3
The equation is in standard form.
\frac{2a}{2}=\frac{5b+3}{2}
Divide both sides by 2.
a=\frac{5b+3}{2}
Dividing by 2 undoes the multiplication by 2.
-5b=3-2a
Subtract 2a from both sides.
\frac{-5b}{-5}=\frac{3-2a}{-5}
Divide both sides by -5.
b=\frac{3-2a}{-5}
Dividing by -5 undoes the multiplication by -5.
b=\frac{2a-3}{5}
Divide 3-2a by -5.
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