Solve 2a-3+7-3a+(-4-a)

$$2 a - 3 + 7 - 3 a + ( - 4 - a )$$

Evaluate

$$-2a$$

Solution Steps

Add -3 and 7 to get 4.

$$2a+4-3a-4-a$$

Combine 2a and -3a to get -a.

$$-a+4-4-a$$

Subtract 4 from 4 to get 0.

$$-a-a$$

Combine -a and -a to get -2a.

$$-2a$$

Differentiate w.r.t. a

$$-2$$

Steps Using Definition of a Derivative

Add -3 and 7 to get 4.

$$\frac{\mathrm{d}}{\mathrm{d}a}(2a+4-3a-4-a)$$

Combine 2a and -3a to get -a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(-a+4-4-a)$$

Subtract 4 from 4 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}a}(-a-a)$$

Combine -a and -a to get -2a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(-2a)$$

The derivative of ax^{n} is nax^{n-1}.

$$-2a^{1-1}$$

Subtract 1 from 1.

$$-2a^{0}$$

For any term t except 0, t^{0}=1.

$$-2$$