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Solve for b
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Solve for a
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3b+4c=-2a^{2}
Subtract 2a^{2} from both sides. Anything subtracted from zero gives its negation.
3b=-2a^{2}-4c
Subtract 4c from both sides.
\frac{3b}{3}=\frac{-2a^{2}-4c}{3}
Divide both sides by 3.
b=\frac{-2a^{2}-4c}{3}
Dividing by 3 undoes the multiplication by 3.