Solve 2a+4b=3

$$2 a + 4 b = 3$$

Solve for a

$$a=\frac{3}{2}-2b$$

Steps for Solving Linear Equation

Subtract 4b from both sides.

$$2a=3-4b$$

Divide both sides by 2.

$$\frac{2a}{2}=\frac{3-4b}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$a=\frac{3-4b}{2}$$

Divide 3-4b by 2.

$$a=\frac{3}{2}-2b$$

Solve for b

$$b=-\frac{a}{2}+\frac{3}{4}$$

Steps for Solving Linear Equation

Subtract 2a from both sides.

$$4b=3-2a$$

Divide both sides by 4.

$$\frac{4b}{4}=\frac{3-2a}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$b=\frac{3-2a}{4}$$

Divide 3-2a by 4.

$$b=-\frac{a}{2}+\frac{3}{4}$$