Solve for a
a=\frac{3-3b}{2}
Solve for b
b=-\frac{2a}{3}+1
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2a=3-3b
Subtract 3b from both sides.
\frac{2a}{2}=\frac{3-3b}{2}
Divide both sides by 2.
a=\frac{3-3b}{2}
Dividing by 2 undoes the multiplication by 2.
3b=3-2a
Subtract 2a from both sides.
\frac{3b}{3}=\frac{3-2a}{3}
Divide both sides by 3.
b=\frac{3-2a}{3}
Dividing by 3 undoes the multiplication by 3.
b=-\frac{2a}{3}+1
Divide 3-2a by 3.
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