Solve for a
a=-\frac{3b}{2}+6
Solve for b
b=-\frac{2a}{3}+4
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2a=12-3b
Subtract 3b from both sides.
\frac{2a}{2}=\frac{12-3b}{2}
Divide both sides by 2.
a=\frac{12-3b}{2}
Dividing by 2 undoes the multiplication by 2.
a=-\frac{3b}{2}+6
Divide 12-3b by 2.
3b=12-2a
Subtract 2a from both sides.
\frac{3b}{3}=\frac{12-2a}{3}
Divide both sides by 3.
b=\frac{12-2a}{3}
Dividing by 3 undoes the multiplication by 3.
b=-\frac{2a}{3}+4
Divide 12-2a by 3.
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