Solve 2a+3a*q=1

$$2 a + 3 a \cdot q = 1$$

Solve for a

$$a=\frac{1}{3q+2}$$

$$q\neq -\frac{2}{3}$$

Steps for Solving Linear Equation

Combine all terms containing a.

$$\left(2+3q\right)a=1$$

The equation is in standard form.

$$\left(3q+2\right)a=1$$

Divide both sides by 2+3q.

$$\frac{\left(3q+2\right)a}{3q+2}=\frac{1}{3q+2}$$

Dividing by 2+3q undoes the multiplication by 2+3q.

$$a=\frac{1}{3q+2}$$

Solve for q

$$q=-\frac{2}{3}+\frac{1}{3a}$$

$$a\neq 0$$

Steps for Solving Linear Equation

Subtract 2a from both sides.

$$3aq=1-2a$$

Divide both sides by 3a.

$$\frac{3aq}{3a}=\frac{1-2a}{3a}$$

Dividing by 3a undoes the multiplication by 3a.

$$q=\frac{1-2a}{3a}$$

Divide 1-2a by 3a.

$$q=-\frac{2}{3}+\frac{1}{3a}$$