Solve 2a+1+3/a-1

$$2 a + 1 + \frac { 3 } { a - 1 }$$

Evaluate

$$\frac{2a^{2}-a+2}{a-1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2a+1 times \frac{a-1}{a-1}.

$$\frac{\left(2a+1\right)\left(a-1\right)}{a-1}+\frac{3}{a-1}$$

Since \frac{\left(2a+1\right)\left(a-1\right)}{a-1} and \frac{3}{a-1} have the same denominator, add them by adding their numerators.

$$\frac{\left(2a+1\right)\left(a-1\right)+3}{a-1}$$

Do the multiplications in \left(2a+1\right)\left(a-1\right)+3.

$$\frac{2a^{2}-2a+a-1+3}{a-1}$$

Combine like terms in 2a^{2}-2a+a-1+3.

$$\frac{2a^{2}-a+2}{a-1}$$

Differentiate w.r.t. a

$$\frac{2a^{2}-4a-1}{\left(a-1\right)^{2}}$$

Steps Using Derivative Rule for Quotient

To add or subtract expressions, expand them to make their denominators the same. Multiply 2a+1 times \frac{a-1}{a-1}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{\left(2a+1\right)\left(a-1\right)}{a-1}+\frac{3}{a-1})$$

Since \frac{\left(2a+1\right)\left(a-1\right)}{a-1} and \frac{3}{a-1} have the same denominator, add them by adding their numerators.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{\left(2a+1\right)\left(a-1\right)+3}{a-1})$$

Do the multiplications in \left(2a+1\right)\left(a-1\right)+3.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{2a^{2}-2a+a-1+3}{a-1})$$

Combine like terms in 2a^{2}-2a+a-1+3.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{2a^{2}-a+2}{a-1})$$

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(a^{1}-1\right)\frac{\mathrm{d}}{\mathrm{d}a}(2a^{2}-a^{1}+2)-\left(2a^{2}-a^{1}+2\right)\frac{\mathrm{d}}{\mathrm{d}a}(a^{1}-1)}{\left(a^{1}-1\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(a^{1}-1\right)\left(2\times 2a^{2-1}-a^{1-1}\right)-\left(2a^{2}-a^{1}+2\right)a^{1-1}}{\left(a^{1}-1\right)^{2}}$$

Simplify.

$$\frac{\left(a^{1}-1\right)\left(4a^{1}-a^{0}\right)-\left(2a^{2}-a^{1}+2\right)a^{0}}{\left(a^{1}-1\right)^{2}}$$

Multiply a^{1}-1 times 4a^{1}-a^{0}.

$$\frac{a^{1}\times 4a^{1}+a^{1}\left(-1\right)a^{0}-4a^{1}-\left(-a^{0}\right)-\left(2a^{2}-a^{1}+2\right)a^{0}}{\left(a^{1}-1\right)^{2}}$$

Multiply 2a^{2}-a^{1}+2 times a^{0}.

$$\frac{a^{1}\times 4a^{1}+a^{1}\left(-1\right)a^{0}-4a^{1}-\left(-a^{0}\right)-\left(2a^{2}a^{0}-a^{1}a^{0}+2a^{0}\right)}{\left(a^{1}-1\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{4a^{1+1}-a^{1}-4a^{1}-\left(-a^{0}\right)-\left(2a^{2}-a^{1}+2a^{0}\right)}{\left(a^{1}-1\right)^{2}}$$

Simplify.

$$\frac{4a^{2}-a^{1}-4a^{1}+a^{0}-\left(2a^{2}-a^{1}+2a^{0}\right)}{\left(a^{1}-1\right)^{2}}$$

Combine like terms.

$$\frac{2a^{2}-4a^{1}-a^{0}}{\left(a^{1}-1\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{2a^{2}-4a-a^{0}}{\left(a-1\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{2a^{2}-4a-1}{\left(a-1\right)^{2}}$$