Solve 2N_{1}+3N_{2}=141

$$2 N _ { 1 } + 3 N _ { 2 } = 141$$

Solve for N_1

$$N_{1}=\frac{141-3N_{2}}{2}$$

Steps for Solving Linear Equation

Subtract 3N_{2} from both sides.

$$2N_{1}=141-3N_{2}$$

Divide both sides by 2.

$$\frac{2N_{1}}{2}=\frac{141-3N_{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$N_{1}=\frac{141-3N_{2}}{2}$$

Solve for N_2

$$N_{2}=-\frac{2N_{1}}{3}+47$$

Steps for Solving Linear Equation

Subtract 2N_{1} from both sides.

$$3N_{2}=141-2N_{1}$$

Divide both sides by 3.

$$\frac{3N_{2}}{3}=\frac{141-2N_{1}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$N_{2}=\frac{141-2N_{1}}{3}$$

Divide 141-2N_{1} by 3.

$$N_{2}=-\frac{2N_{1}}{3}+47$$