Solve 2A*4A=

$$2 A \times 4 A =$$

Evaluate

$$8A^{2}$$

Solution Steps

Multiply A and A to get A^{2}.

$$2A^{2}\times 4$$

Multiply 2 and 4 to get 8.

$$8A^{2}$$

Differentiate w.r.t. A

$$16A$$

Steps Using Definition of a Derivative

Multiply A and A to get A^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}A}(2A^{2}\times 4)$$

Multiply 2 and 4 to get 8.

$$\frac{\mathrm{d}}{\mathrm{d}A}(8A^{2})$$

The derivative of ax^{n} is nax^{n-1}.

$$2\times 8A^{2-1}$$

Multiply 2 times 8.

$$16A^{2-1}$$

Subtract 1 from 2.

$$16A^{1}$$

For any term t, t^{1}=t.

$$16A$$