Solve for A
A=\frac{3t+\pi k^{2}}{2}
Solve for k
k=\sqrt{\frac{2A-3t}{\pi }}
k=-\sqrt{\frac{2A-3t}{\pi }}\text{, }A\geq \frac{3t}{2}
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2A=3t+\pi k^{2}
The equation is in standard form.
\frac{2A}{2}=\frac{3t+\pi k^{2}}{2}
Divide both sides by 2.
A=\frac{3t+\pi k^{2}}{2}
Dividing by 2 undoes the multiplication by 2.
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