Solve for x
x=2\left(y+4\right)
Solve for y
y=\frac{x-8}{2}
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8-4y=x-6y
Multiply both sides of the equation by 4.
x-6y=8-4y
Swap sides so that all variable terms are on the left hand side.
x=8-4y+6y
Add 6y to both sides.
x=8+2y
Combine -4y and 6y to get 2y.
8-4y=x-6y
Multiply both sides of the equation by 4.
8-4y+6y=x
Add 6y to both sides.
8+2y=x
Combine -4y and 6y to get 2y.
2y=x-8
Subtract 8 from both sides.
\frac{2y}{2}=\frac{x-8}{2}
Divide both sides by 2.
y=\frac{x-8}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{x}{2}-4
Divide x-8 by 2.
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\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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