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-3x=\sqrt{2}+\sqrt{3}-2
Subtract 2 from both sides.
\frac{-3x}{-3}=\frac{\sqrt{2}+\sqrt{3}-2}{-3}
Divide both sides by -3.
x=\frac{\sqrt{2}+\sqrt{3}-2}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{2-\sqrt{2}-\sqrt{3}}{3}
Divide \sqrt{2}+\sqrt{3}-2 by -3.