Solve 2-3(y+1)=1-2(1+0.5y)

$$2 - 3 ( y + 1 ) = 1 - 2 ( 1 + 0.5 y )$$

Solve for y

$$y=0$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by y+1.

$$2-3y-3=1-2\left(1+0.5y\right)$$

Subtract 3 from 2 to get -1.

$$-1-3y=1-2\left(1+0.5y\right)$$

Use the distributive property to multiply -2 by 1+0.5y.

$$-1-3y=1-2-y$$

Subtract 2 from 1 to get -1.

$$-1-3y=-1-y$$

Add y to both sides.

$$-1-3y+y=-1$$

Combine -3y and y to get -2y.

$$-1-2y=-1$$

Add 1 to both sides.

$$-2y=-1+1$$

Add -1 and 1 to get 0.

$$-2y=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -2 is not equal to 0, y must be equal to 0.

$$y=0$$