Solve 2-13/4=3/4-13/4=10/4=

$$2 - 1 \frac { 3 } { 4 } = \frac { 3 } { 4 } - 1 \frac { 3 } { 4 } = 1 \frac { 0 } { 4 } =$$

Verify

Solution Steps

Multiply 1 and 4 to get 4.

$$2-\frac{4+3}{4}=\frac{3}{4}-\frac{1\times 4+3}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Add 4 and 3 to get 7.

$$2-\frac{7}{4}=\frac{3}{4}-\frac{1\times 4+3}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Convert 2 to fraction \frac{8}{4}.

$$\frac{8}{4}-\frac{7}{4}=\frac{3}{4}-\frac{1\times 4+3}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Since \frac{8}{4} and \frac{7}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-7}{4}=\frac{3}{4}-\frac{1\times 4+3}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Subtract 7 from 8 to get 1.

$$\frac{1}{4}=\frac{3}{4}-\frac{1\times 4+3}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Multiply 1 and 4 to get 4.

$$\frac{1}{4}=\frac{3}{4}-\frac{4+3}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Add 4 and 3 to get 7.

$$\frac{1}{4}=\frac{3}{4}-\frac{7}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Since \frac{3}{4} and \frac{7}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{4}=\frac{3-7}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Subtract 7 from 3 to get -4.

$$\frac{1}{4}=\frac{-4}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Divide -4 by 4 to get -1.

$$\frac{1}{4}=-1\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Convert -1 to fraction -\frac{4}{4}.

$$\frac{1}{4}=-\frac{4}{4}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Compare \frac{1}{4} and -\frac{4}{4}.

$$\text{false}\text{ and }\frac{3}{4}-\frac{1\times 4+3}{4}=\frac{1\times 4+0}{4}$$

Multiply 1 and 4 to get 4.

$$\text{false}\text{ and }\frac{3}{4}-\frac{4+3}{4}=\frac{1\times 4+0}{4}$$

Add 4 and 3 to get 7.

$$\text{false}\text{ and }\frac{3}{4}-\frac{7}{4}=\frac{1\times 4+0}{4}$$

Since \frac{3}{4} and \frac{7}{4} have the same denominator, subtract them by subtracting their numerators.

$$\text{false}\text{ and }\frac{3-7}{4}=\frac{1\times 4+0}{4}$$

Subtract 7 from 3 to get -4.

$$\text{false}\text{ and }\frac{-4}{4}=\frac{1\times 4+0}{4}$$

Divide -4 by 4 to get -1.

$$\text{false}\text{ and }-1=\frac{1\times 4+0}{4}$$

Multiply 1 and 4 to get 4.

$$\text{false}\text{ and }-1=\frac{4+0}{4}$$

Add 4 and 0 to get 4.

$$\text{false}\text{ and }-1=\frac{4}{4}$$

Divide 4 by 4 to get 1.

$$\text{false}\text{ and }-1=1$$

Compare -1 and 1.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$