Solve 2-(-7/4)^2+(-5/8)=-16/27

$$2 - ( - \frac { 7 } { 4 } ) ^ { 2 } + ( - \frac { 5 } { 8 } ) = - \frac { 16 } { 27 }$$

Verify

Solution Steps

Calculate -\frac{7}{4} to the power of 2 and get \frac{49}{16}.

$$2-\frac{49}{16}-\frac{5}{8}=-\frac{16}{27}$$

Convert 2 to fraction \frac{32}{16}.

$$\frac{32}{16}-\frac{49}{16}-\frac{5}{8}=-\frac{16}{27}$$

Since \frac{32}{16} and \frac{49}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{32-49}{16}-\frac{5}{8}=-\frac{16}{27}$$

Subtract 49 from 32 to get -17.

$$-\frac{17}{16}-\frac{5}{8}=-\frac{16}{27}$$

Least common multiple of 16 and 8 is 16. Convert -\frac{17}{16} and \frac{5}{8} to fractions with denominator 16.

$$-\frac{17}{16}-\frac{10}{16}=-\frac{16}{27}$$

Since -\frac{17}{16} and \frac{10}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-17-10}{16}=-\frac{16}{27}$$

Subtract 10 from -17 to get -27.

$$-\frac{27}{16}=-\frac{16}{27}$$

Least common multiple of 16 and 27 is 432. Convert -\frac{27}{16} and -\frac{16}{27} to fractions with denominator 432.

$$-\frac{729}{432}=-\frac{256}{432}$$

Compare -\frac{729}{432} and -\frac{256}{432}.

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