Solve 2-(frac{sqrt{6}}{3})^2

$$2 - ( \frac { \sqrt { 6 } } { 3 } ) ^ { 2 }$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

To raise \frac{\sqrt{6}}{3} to a power, raise both numerator and denominator to the power and then divide.

$$2-\frac{\left(\sqrt{6}\right)^{2}}{3^{2}}$$

The square of \sqrt{6} is 6.

$$2-\frac{6}{3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$2-\frac{6}{9}$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$2-\frac{2}{3}$$

Subtract \frac{2}{3} from 2 to get \frac{4}{3}.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$