Solve 2-sqrt{(-2)^6}:(-2)+sqrt{(-4)^2}(-4)

$$2 - \sqrt { ( - 2 ) ^ { 6 } } : ( - 2 ) + \sqrt { ( - 4 ) ^ { 2 } } ( - 4 )$$

Evaluate

$$-10$$

Solution Steps

Calculate -2 to the power of 6 and get 64.

$$2-\frac{\sqrt{64}}{-2}+\sqrt{\left(-4\right)^{2}}\left(-4\right)$$

Calculate the square root of 64 and get 8.

$$2-\frac{8}{-2}+\sqrt{\left(-4\right)^{2}}\left(-4\right)$$

Divide 8 by -2 to get -4.

$$2-\left(-4\right)+\sqrt{\left(-4\right)^{2}}\left(-4\right)$$

The opposite of -4 is 4.

$$2+4+\sqrt{\left(-4\right)^{2}}\left(-4\right)$$

Add 2 and 4 to get 6.

$$6+\sqrt{\left(-4\right)^{2}}\left(-4\right)$$

Calculate -4 to the power of 2 and get 16.

$$6+\sqrt{16}\left(-4\right)$$

Calculate the square root of 16 and get 4.

$$6+4\left(-4\right)$$

Multiply 4 and -4 to get -16.

$$6-16$$

Subtract 16 from 6 to get -10.

$$-10$$

Factor

$$-10$$