Solve 2-5/3+7+2/5-3=

$$2 - \frac { 5 } { 3 } + 7 + \frac { 2 } { 5 } - 3 =$$

Evaluate

$$\frac{71}{15}\approx 4.733333333$$

Solution Steps

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}-\frac{5}{3}+7+\frac{2}{5}-3$$

Since \frac{6}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-5}{3}+7+\frac{2}{5}-3$$

Subtract 5 from 6 to get 1.

$$\frac{1}{3}+7+\frac{2}{5}-3$$

Convert 7 to fraction \frac{21}{3}.

$$\frac{1}{3}+\frac{21}{3}+\frac{2}{5}-3$$

Since \frac{1}{3} and \frac{21}{3} have the same denominator, add them by adding their numerators.

$$\frac{1+21}{3}+\frac{2}{5}-3$$

Add 1 and 21 to get 22.

$$\frac{22}{3}+\frac{2}{5}-3$$

Least common multiple of 3 and 5 is 15. Convert \frac{22}{3} and \frac{2}{5} to fractions with denominator 15.

$$\frac{110}{15}+\frac{6}{15}-3$$

Since \frac{110}{15} and \frac{6}{15} have the same denominator, add them by adding their numerators.

$$\frac{110+6}{15}-3$$

Add 110 and 6 to get 116.

$$\frac{116}{15}-3$$

Convert 3 to fraction \frac{45}{15}.

$$\frac{116}{15}-\frac{45}{15}$$

Since \frac{116}{15} and \frac{45}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{116-45}{15}$$

Subtract 45 from 116 to get 71.

$$\frac{71}{15}$$

Factor

$$\frac{71}{3 \cdot 5} = 4\frac{11}{15} = 4.733333333333333$$