Solve 2-2/3(3q-7)

$$2 - \frac { 2 } { 3 } ( 3 q - 7 )$$

Evaluate

$$\frac{20}{3}-2q$$

Solution Steps

Use the distributive property to multiply -\frac{2}{3} by 3q-7.

$$2-\frac{2}{3}\times 3q-\frac{2}{3}\left(-7\right)$$

Cancel out 3 and 3.

$$2-2q-\frac{2}{3}\left(-7\right)$$

Express -\frac{2}{3}\left(-7\right) as a single fraction.

$$2-2q+\frac{-2\left(-7\right)}{3}$$

Multiply -2 and -7 to get 14.

$$2-2q+\frac{14}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}-2q+\frac{14}{3}$$

Since \frac{6}{3} and \frac{14}{3} have the same denominator, add them by adding their numerators.

$$\frac{6+14}{3}-2q$$

Add 6 and 14 to get 20.

$$\frac{20}{3}-2q$$

Expand

$$\frac{20}{3}-2q$$

Solution Steps

Use the distributive property to multiply -\frac{2}{3} by 3q-7.

$$2-\frac{2}{3}\times 3q-\frac{2}{3}\left(-7\right)$$

Cancel out 3 and 3.

$$2-2q-\frac{2}{3}\left(-7\right)$$

Express -\frac{2}{3}\left(-7\right) as a single fraction.

$$2-2q+\frac{-2\left(-7\right)}{3}$$

Multiply -2 and -7 to get 14.

$$2-2q+\frac{14}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}-2q+\frac{14}{3}$$

Since \frac{6}{3} and \frac{14}{3} have the same denominator, add them by adding their numerators.

$$\frac{6+14}{3}-2q$$

Add 6 and 14 to get 20.

$$\frac{20}{3}-2q$$