Solve 2-1/4-(-1/8)-1/10=

$$2 - \frac { 1 } { 4 } - ( \frac { - 1 } { 8 } ) - \frac { 1 } { 10 } =$$

Evaluate

$$\frac{71}{40}=1.775$$

Solution Steps

Convert 2 to fraction \frac{8}{4}.

$$\frac{8}{4}-\frac{1}{4}-\frac{-1}{8}-\frac{1}{10}$$

Since \frac{8}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-1}{4}-\frac{-1}{8}-\frac{1}{10}$$

Subtract 1 from 8 to get 7.

$$\frac{7}{4}-\frac{-1}{8}-\frac{1}{10}$$

Fraction \frac{-1}{8} can be rewritten as -\frac{1}{8} by extracting the negative sign.

$$\frac{7}{4}-\left(-\frac{1}{8}\right)-\frac{1}{10}$$

The opposite of -\frac{1}{8} is \frac{1}{8}.

$$\frac{7}{4}+\frac{1}{8}-\frac{1}{10}$$

Least common multiple of 4 and 8 is 8. Convert \frac{7}{4} and \frac{1}{8} to fractions with denominator 8.

$$\frac{14}{8}+\frac{1}{8}-\frac{1}{10}$$

Since \frac{14}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{14+1}{8}-\frac{1}{10}$$

Add 14 and 1 to get 15.

$$\frac{15}{8}-\frac{1}{10}$$

Least common multiple of 8 and 10 is 40. Convert \frac{15}{8} and \frac{1}{10} to fractions with denominator 40.

$$\frac{75}{40}-\frac{4}{40}$$

Since \frac{75}{40} and \frac{4}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{75-4}{40}$$

Subtract 4 from 75 to get 71.

$$\frac{71}{40}$$

Factor

$$\frac{71}{2 ^ {3} \cdot 5} = 1\frac{31}{40} = 1.775$$