Solve 2-1/3(x-2)=4

$$2 - \frac { 1 } { 3 } ( x - 2 ) = 4$$

Solve for x

$$x=-4$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{3} by x-2.

$$2-\frac{1}{3}x-\frac{1}{3}\left(-2\right)=4$$

Express -\frac{1}{3}\left(-2\right) as a single fraction.

$$2-\frac{1}{3}x+\frac{-\left(-2\right)}{3}=4$$

Multiply -1 and -2 to get 2.

$$2-\frac{1}{3}x+\frac{2}{3}=4$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}-\frac{1}{3}x+\frac{2}{3}=4$$

Since \frac{6}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{6+2}{3}-\frac{1}{3}x=4$$

Add 6 and 2 to get 8.

$$\frac{8}{3}-\frac{1}{3}x=4$$

Subtract \frac{8}{3} from both sides.

$$-\frac{1}{3}x=4-\frac{8}{3}$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{1}{3}x=\frac{12}{3}-\frac{8}{3}$$

Since \frac{12}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{3}x=\frac{12-8}{3}$$

Subtract 8 from 12 to get 4.

$$-\frac{1}{3}x=\frac{4}{3}$$

Multiply both sides by -3, the reciprocal of -\frac{1}{3}.

$$x=\frac{4}{3}\left(-3\right)$$

Express \frac{4}{3}\left(-3\right) as a single fraction.

$$x=\frac{4\left(-3\right)}{3}$$

Multiply 4 and -3 to get -12.

$$x=\frac{-12}{3}$$

Divide -12 by 3 to get -4.

$$x=-4$$