Solve for m
m=1
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2-\frac{1}{3}m-\frac{1}{3}\left(-1\right)=2
Use the distributive property to multiply -\frac{1}{3} by m-1.
2-\frac{1}{3}m+\frac{1}{3}=2
Multiply -\frac{1}{3} and -1 to get \frac{1}{3}.
\frac{6}{3}-\frac{1}{3}m+\frac{1}{3}=2
Convert 2 to fraction \frac{6}{3}.
\frac{6+1}{3}-\frac{1}{3}m=2
Since \frac{6}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.
\frac{7}{3}-\frac{1}{3}m=2
Add 6 and 1 to get 7.
-\frac{1}{3}m=2-\frac{7}{3}
Subtract \frac{7}{3} from both sides.
-\frac{1}{3}m=\frac{6}{3}-\frac{7}{3}
Convert 2 to fraction \frac{6}{3}.
-\frac{1}{3}m=\frac{6-7}{3}
Since \frac{6}{3} and \frac{7}{3} have the same denominator, subtract them by subtracting their numerators.
-\frac{1}{3}m=-\frac{1}{3}
Subtract 7 from 6 to get -1.
m=-\frac{1}{3}\left(-3\right)
Multiply both sides by -3, the reciprocal of -\frac{1}{3}.
m=\frac{-\left(-3\right)}{3}
Express -\frac{1}{3}\left(-3\right) as a single fraction.
m=\frac{3}{3}
Multiply -1 and -3 to get 3.
m=1
Divide 3 by 3 to get 1.
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