Solve 2-3-2(-3+1)^2-3-2[4-(3+2)^2]

$$2 - \{ 3 - 2 ( - 3 + 1 ) \} ^ { 2 } - 3 - 2 [ 4 - ( 3 + 2 ) ^ { 2 } ]$$

Evaluate

$$-8$$

Solution Steps

Add -3 and 1 to get -2.

$$2-\left(3-2\left(-2\right)\right)^{2}-3-2\left(4-\left(3+2\right)^{2}\right)$$

Multiply 2 and -2 to get -4.

$$2-\left(3-\left(-4\right)\right)^{2}-3-2\left(4-\left(3+2\right)^{2}\right)$$

The opposite of -4 is 4.

$$2-\left(3+4\right)^{2}-3-2\left(4-\left(3+2\right)^{2}\right)$$

Add 3 and 4 to get 7.

$$2-7^{2}-3-2\left(4-\left(3+2\right)^{2}\right)$$

Calculate 7 to the power of 2 and get 49.

$$2-49-3-2\left(4-\left(3+2\right)^{2}\right)$$

Subtract 49 from 2 to get -47.

$$-47-3-2\left(4-\left(3+2\right)^{2}\right)$$

Subtract 3 from -47 to get -50.

$$-50-2\left(4-\left(3+2\right)^{2}\right)$$

Add 3 and 2 to get 5.

$$-50-2\left(4-5^{2}\right)$$

Calculate 5 to the power of 2 and get 25.

$$-50-2\left(4-25\right)$$

Subtract 25 from 4 to get -21.

$$-50-2\left(-21\right)$$

Multiply 2 and -21 to get -42.

$$-50-\left(-42\right)$$

The opposite of -42 is 42.

$$-50+42$$

Add -50 and 42 to get -8.

$$-8$$

Factor

$$-8$$