Solve 2-[3-(2-5)*3+2*(1-3)*(-2)]+5

$$2 - [ 3 - ( 2 - 5 ) \cdot 3 + 2 \cdot ( 1 - 3 ) \cdot ( - 2 ) ] + 5$$

Evaluate

$$-13$$

Solution Steps

Subtract 5 from 2 to get -3.

$$2-\left(3-\left(-3\times 3\right)+2\left(1-3\right)\left(-2\right)\right)+5$$

Multiply -3 and 3 to get -9.

$$2-\left(3-\left(-9\right)+2\left(1-3\right)\left(-2\right)\right)+5$$

The opposite of -9 is 9.

$$2-\left(3+9+2\left(1-3\right)\left(-2\right)\right)+5$$

Add 3 and 9 to get 12.

$$2-\left(12+2\left(1-3\right)\left(-2\right)\right)+5$$

Subtract 3 from 1 to get -2.

$$2-\left(12+2\left(-2\right)\left(-2\right)\right)+5$$

Multiply 2 and -2 to get -4.

$$2-\left(12-4\left(-2\right)\right)+5$$

Multiply -4 and -2 to get 8.

$$2-\left(12+8\right)+5$$

Add 12 and 8 to get 20.

$$2-20+5$$

Subtract 20 from 2 to get -18.

$$-18+5$$

Add -18 and 5 to get -13.

$$-13$$

Factor

$$-13$$