Solve 2(z-1)-5=3(3+z)+z

$$2 ( z - 1 ) - 5 = 3 ( 3 + z ) + z$$

Solve for z

$$z=-8$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by z-1.

$$2z-2-5=3\left(3+z\right)+z$$

Subtract 5 from -2 to get -7.

$$2z-7=3\left(3+z\right)+z$$

Use the distributive property to multiply 3 by 3+z.

$$2z-7=9+3z+z$$

Combine 3z and z to get 4z.

$$2z-7=9+4z$$

Subtract 4z from both sides.

$$2z-7-4z=9$$

Combine 2z and -4z to get -2z.

$$-2z-7=9$$

Add 7 to both sides.

$$-2z=9+7$$

Add 9 and 7 to get 16.

$$-2z=16$$

Divide both sides by -2.

$$z=\frac{16}{-2}$$

Divide 16 by -2 to get -8.

$$z=-8$$