Solve 2(y+4)geq7(y-1)

$$2 ( y + 4 ) \geq 7 ( y - 1 )$$

Solve for y

$$y\leq 3$$

Solution Steps

Use the distributive property to multiply 2 by y+4.

$$2y+8\geq 7\left(y-1\right)$$

Use the distributive property to multiply 7 by y-1.

$$2y+8\geq 7y-7$$

Subtract 7y from both sides.

$$2y+8-7y\geq -7$$

Combine 2y and -7y to get -5y.

$$-5y+8\geq -7$$

Subtract 8 from both sides.

$$-5y\geq -7-8$$

Subtract 8 from -7 to get -15.

$$-5y\geq -15$$

Divide both sides by -5. Since -5 is negative, the inequality direction is changed.

$$y\leq \frac{-15}{-5}$$

Divide -15 by -5 to get 3.

$$y\leq 3$$