Solve 2(x-3)+3(x+1)=7x-1

$$2 ( x - 3 ) + 3 ( x + 1 ) = 7 x - 1$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by x-3.

$$2x-6+3\left(x+1\right)=7x-1$$

Use the distributive property to multiply 3 by x+1.

$$2x-6+3x+3=7x-1$$

Combine 2x and 3x to get 5x.

$$5x-6+3=7x-1$$

Add -6 and 3 to get -3.

$$5x-3=7x-1$$

Subtract 7x from both sides.

$$5x-3-7x=-1$$

Combine 5x and -7x to get -2x.

$$-2x-3=-1$$

Add 3 to both sides.

$$-2x=-1+3$$

Add -1 and 3 to get 2.

$$-2x=2$$

Divide both sides by -2.

$$x=\frac{2}{-2}$$

Divide 2 by -2 to get -1.

$$x=-1$$